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A triangular garden bed is set out. In triangle ABC, side AB = 13 m, side BC = 14 m, and the angle ABC = 50°.

Find the area of the triangle, correct to one decimal place (in square metres).

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Worked solution — answer: 69.7

A = ½ab sin C

= ½ × 13 × 14 × sin 50°

= 69.7 m²

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